m^2-38m-36=0

Solution for m^2-38m-36=0 equation:

m^2-38m-36=0

a = 1; b = -38; c = -36;
Δ = b2-4ac
Δ = -382-4·1·(-36)
Δ = 1588
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1588}=\sqrt{4*397}=\sqrt{4}*\sqrt{397}=2\sqrt{397}$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-38)-2\sqrt{397}}{2*1}=\frac{38-2\sqrt{397}}{2}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-38)+2\sqrt{397}}{2*1}=\frac{38+2\sqrt{397}}{2}
$